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(y^2+9)-6(4+y)=-24
We move all terms to the left:
(y^2+9)-6(4+y)-(-24)=0
We add all the numbers together, and all the variables
(y^2+9)-6(y+4)-(-24)=0
We add all the numbers together, and all the variables
(y^2+9)-6(y+4)+24=0
We multiply parentheses
(y^2+9)-6y-24+24=0
We get rid of parentheses
y^2-6y+9-24+24=0
We add all the numbers together, and all the variables
y^2-6y+9=0
a = 1; b = -6; c = +9;
Δ = b2-4ac
Δ = -62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{6}{2}=3$
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